apabila sin teta =5/13 dan sudut teta lancip ,maka nilai dari 1-2 Cos teta adalah
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inθ = 5/13 (θ ∠lancip)
Cos²θ = 1 - sin²θ
cos²θ = 1- (5/13)²
cos²θ = 1 - 25/169
cos²θ = 169/169 - 25/169
cos²θ = 144/169
cosθ = 12/13
tanθ = sinθ/cosθ
tanθ = (5/13)/(12/13)
tanθ = 5/12
.
√(1 + tanθ)(1 - tanθ))
√(1 - tan²θ)
√ [1 - (5/12)²]
√( 1 - 25/144)
√( 144/144 - 25/144)
√(119/144)
[answer.2.content]
